Question Number 199165 by hardmath last updated on 28/Oct/23
Answered by Frix last updated on 28/Oct/23
$$−\mathrm{1}=\mathrm{e}^{\mathrm{i}\pi} \\ $$$$\left(−\mathrm{1}\right)^{\pi} =\mathrm{e}^{\mathrm{i}\pi^{\mathrm{2}} } = \\ $$$$=\mathrm{cos}\:\pi^{\mathrm{2}} \:+\mathrm{i}\:\mathrm{sin}\:\pi^{\mathrm{2}} \\ $$$$\approx−.\mathrm{902685362}+−.\mathrm{430301217i} \\ $$