Question Number 199520 by tri26112004 last updated on 04/Nov/23
$${n}^{\mathrm{4}} +{an}^{\mathrm{3}} +{bn}^{\mathrm{2}} +{cn}+{d}={k}^{\mathrm{2}} \:\left({k}\in{N}\right) \\ $$$${a},{b},{c},{d}=¿ \\ $$
Answered by Frix last updated on 04/Nov/23
$$\mathrm{You}\:\mathrm{can}\:\mathrm{choose}\:{n},\:{a},\:{b},\:{c},\:{k}\:\in\mathbb{N}\:\mathrm{and}\:\mathrm{find}\:{d}. \\ $$$$\mathrm{There}'\mathrm{s}\:\mathrm{no}\:\mathrm{unique}\:\mathrm{solution}. \\ $$