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Find-all-possible-value-a-a-b-d-b-a-b-c-c-b-c-d-d-a-c-d-when-a-b-c-d-vary-over-positive-reals-




Question Number 199847 by cortano12 last updated on 10/Nov/23
 Find all possible value    (a/(a+b+d )) +(b/(a+b+c)) + (c/(b+c+d))+(d/(a+c+d))    when a,b,c,d vary over positive   reals
Findallpossiblevalueaa+b+d+ba+b+c+cb+c+d+da+c+dwhena,b,c,dvaryoverpositivereals
Commented by Frix last updated on 10/Nov/23
No problem! I′m also trying...  I think 1≤f is true but f<2?
Noproblem!ImalsotryingIthink1fistruebutf<2?
Commented by witcher3 last updated on 10/Nov/23
i didnt want delate Y re coment
ididntwantdelateYrecoment
Commented by witcher3 last updated on 10/Nov/23
sorry frix my solution is false
sorryfrixmysolutionisfalse
Commented by witcher3 last updated on 12/Nov/23
f<2 i?think also
f<2i?thinkalso
Commented by witcher3 last updated on 12/Nov/23
if a+b+c>d or evry sum of three ≥forthe  we get f≤(4/3)
ifa+b+c>dorevrysumofthreeforthewegetf43
Commented by Frix last updated on 12/Nov/23
f(a, b, c, d)=(a/(a+b+0c+d))+(b/(a+b+c+0d))+(c/(0a+b+c+d))+(d/(a+0b+c+d))  f(x, x, y, y)=((2(x^2 +4xy+y^2 ))/((x+2y)(2x+y))) ⇒ 1≤f≤(4/3)  f(x, y, x, y)=((4(x^2 +xy+y^2 ))/((x+2y)(2x+y))) ⇒ (4/3)≤f≤2  This is still no proof...
f(a,b,c,d)=aa+b+0c+d+ba+b+c+0d+c0a+b+c+d+da+0b+c+df(x,x,y,y)=2(x2+4xy+y2)(x+2y)(2x+y)1f43f(x,y,x,y)=4(x2+xy+y2)(x+2y)(2x+y)43f2Thisisstillnoproof

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