Menu Close

solve-by-laplce-transform-y-y-y-x-1-e-x-




Question Number 199891 by Mathspace last updated on 10/Nov/23
solve by laplce transform  y^(′′) −y^′ +y =(x+1)e^x
$${solve}\:{by}\:{laplce}\:{transform} \\ $$$${y}^{''} −{y}^{'} +{y}\:=\left({x}+\mathrm{1}\right){e}^{{x}} \\ $$
Commented by Mathspace last updated on 10/Nov/23
with y(0)=1 and y^′ (0)=−1
$${with}\:{y}\left(\mathrm{0}\right)=\mathrm{1}\:{and}\:{y}^{'} \left(\mathrm{0}\right)=−\mathrm{1} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *