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Question-200075




Question Number 200075 by sonukgindia last updated on 13/Nov/23
Answered by ajfour last updated on 13/Nov/23
Rcos θ=((a+b)/2)  R=bcos θ  ⇒  2bcos^2 θ=a+b  (a/b)=2cos^2 θ−1
$${R}\mathrm{cos}\:\theta=\frac{{a}+{b}}{\mathrm{2}} \\ $$$${R}={b}\mathrm{cos}\:\theta \\ $$$$\Rightarrow\:\:\mathrm{2}{b}\mathrm{cos}\:^{\mathrm{2}} \theta={a}+{b} \\ $$$$\frac{{a}}{{b}}=\mathrm{2cos}\:^{\mathrm{2}} \theta−\mathrm{1} \\ $$
Commented by ajfour last updated on 13/Nov/23
Commented by mr W last updated on 14/Nov/23
excellent solution!
$${excellent}\:{solution}! \\ $$

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