Question Number 200110 by sonukgindia last updated on 14/Nov/23
Answered by mr W last updated on 14/Nov/23
$${x}^{{x}^{{x}} } ={x}^{\mathrm{3}} \\ $$$$\Rightarrow{x}=\pm\mathrm{1} \\ $$$$\Rightarrow{x}^{{x}} =\mathrm{3}\Rightarrow{e}^{\mathrm{ln}\:{x}} \mathrm{ln}\:{x}=\mathrm{ln}\:\mathrm{3}\:\Rightarrow{x}=\frac{\mathrm{ln}\:\mathrm{3}}{{W}\left(\mathrm{ln}\:\mathrm{3}\right)}\approx\mathrm{1}.\mathrm{825455} \\ $$