Question Number 200773 by cortano12 last updated on 23/Nov/23
Answered by cherokeesay last updated on 23/Nov/23
Answered by Bharathi last updated on 23/Nov/23
$$\:\:\:\mathrm{Suppose}\:\mathrm{square}\:\mathrm{side}\:\mathrm{be}\:{a} \\ $$$$\:\:\:\:{a}\sqrt{\mathrm{2}}\:=\:\mathrm{3}\left(\mathrm{1}+\sqrt{\mathrm{2}}\:\right) \\ $$$$\:\:\:{a}\:=\:\frac{\mathrm{3}\left(\mathrm{1}+\sqrt{\mathrm{2}}\:\right)}{\:\sqrt{\mathrm{2}}}\: \\ $$$$\:\:\:{a}^{\mathrm{2}} \:=\:\frac{\mathrm{9}\left(\mathrm{3}+\mathrm{2}\sqrt{\mathrm{2}}\:\right)}{\mathrm{2}} \\ $$