Menu Close

Question-200925




Question Number 200925 by akolade last updated on 26/Nov/23
Answered by mr W last updated on 26/Nov/23
p=AB^(→) =(6, −14)  C=(1,5)+(1/4)(6, −14)=(2.5, 1.5)  D=(1,5)+(2/4)(6, −14)=(4, −2)  E=(1,5)+(3/4)(6, −14)=(5.5, −5.5)
$$\boldsymbol{{p}}=\overset{\rightarrow} {{AB}}=\left(\mathrm{6},\:−\mathrm{14}\right) \\ $$$${C}=\left(\mathrm{1},\mathrm{5}\right)+\frac{\mathrm{1}}{\mathrm{4}}\left(\mathrm{6},\:−\mathrm{14}\right)=\left(\mathrm{2}.\mathrm{5},\:\mathrm{1}.\mathrm{5}\right) \\ $$$${D}=\left(\mathrm{1},\mathrm{5}\right)+\frac{\mathrm{2}}{\mathrm{4}}\left(\mathrm{6},\:−\mathrm{14}\right)=\left(\mathrm{4},\:−\mathrm{2}\right) \\ $$$${E}=\left(\mathrm{1},\mathrm{5}\right)+\frac{\mathrm{3}}{\mathrm{4}}\left(\mathrm{6},\:−\mathrm{14}\right)=\left(\mathrm{5}.\mathrm{5},\:−\mathrm{5}.\mathrm{5}\right) \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *