Question Number 201144 by sts313 last updated on 30/Nov/23
$$\left(\frac{\mathrm{14}}{\mathrm{15}}\right)^{\mathrm{6}} ×\left(\frac{\mathrm{45}}{\mathrm{28}}\right)^{\mathrm{6}} = \\ $$
Answered by mathlove last updated on 01/Dec/23
$$\left(\frac{\mathrm{14}}{\mathrm{15}}\right)^{\mathrm{6}} ×\left(\frac{\mathrm{3}×\mathrm{15}}{\mathrm{2}×\mathrm{14}}\right)^{\mathrm{6}} =\frac{\cancel{\mathrm{14}^{\mathrm{6}} }}{\cancel{\mathrm{15}^{\mathrm{6}} }}×\frac{\mathrm{3}^{\mathrm{6}} ×\cancel{\mathrm{15}^{\mathrm{6}} }}{\mathrm{2}^{\mathrm{6}} ×\cancel{\mathrm{14}^{\mathrm{6}} }} \\ $$$$=\left(\frac{\mathrm{3}}{\mathrm{2}}\right)^{\mathrm{6}} \\ $$
Answered by Rasheed.Sindhi last updated on 01/Dec/23
$$\mathrm{Another}\:\mathrm{way} \\ $$$$\left(\frac{\mathrm{14}}{\mathrm{15}}\right)^{\mathrm{6}} ×\left(\frac{\mathrm{45}}{\mathrm{28}}\right)^{\mathrm{6}} =\left(\frac{\cancel{\overset{\mathrm{1}} {\mathrm{14}}}}{\cancel{\underset{\mathrm{1}} {\mathrm{15}}}}×\frac{\cancel{\overset{\mathrm{3}} {\mathrm{45}}}}{\cancel{\underset{\mathrm{2}} {\mathrm{28}}}}\right)^{\mathrm{6}} =\frac{\mathrm{3}^{\mathrm{6}} }{\mathrm{2}^{\mathrm{6}} }=\frac{\mathrm{729}}{\mathrm{64}} \\ $$