Question Number 201135 by 281981 last updated on 30/Nov/23
Answered by MM42 last updated on 30/Nov/23
$${SX}+{SM}=\left({m}+{n}\right)\left(\mathrm{4}{a}−{b}\right) \\ $$$$\frac{\mathrm{9}}{\mathrm{5}}{SM}=\left({m}+{n}\right)\left(\mathrm{4}{a}−{b}\right) \\ $$$$\frac{\mathrm{9}}{\mathrm{5}}\left({SP}+{PQ}+{QM}\right)=\left({m}+{n}\right)\left(\mathrm{4}{a}−{b}\right) \\ $$$$\frac{\mathrm{9}}{\mathrm{5}}\left(\frac{\mathrm{4}{a}−{b}}{\mathrm{2}}\right)=\left({m}+{n}\right)\left(\mathrm{4}{a}−{b}\right) \\ $$$$\Rightarrow{m}+{n}=\frac{\mathrm{9}}{\mathrm{10}}\:\:\checkmark\:\:\left(\mathrm{1}\right) \\ $$$$ \\ $$
Commented by 281981 last updated on 01/Dec/23
$${tna}\:{sir} \\ $$