Question Number 201510 by Calculusboy last updated on 08/Dec/23
Answered by MathematicalUser2357 last updated on 04/Jan/24
![=−2tan^(−1) [cos{(1/2)(t−sin t)}cosec{(1/2)(t−sin t)}]+C](https://www.tinkutara.com/question/Q202839.png)
$$=−\mathrm{2tan}^{−\mathrm{1}} \left[\mathrm{cos}\left\{\frac{\mathrm{1}}{\mathrm{2}}\left({t}−\mathrm{sin}\:{t}\right)\right\}\mathrm{cosec}\left\{\frac{\mathrm{1}}{\mathrm{2}}\left({t}−\mathrm{sin}\:{t}\right)\right\}\right]+{C} \\ $$