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Question-201906




Question Number 201906 by sonukgindia last updated on 15/Dec/23
Answered by AST last updated on 15/Dec/23
sin(x)=(s/h)...(i)  (ii)...((sin(2x))/h)=((sin(x))/(2s))⇒2sin(x)=((sin(x))/(sin(2x)))  ⇒sin(2x)=(1/2)⇒x=15°
sin(x)=sh(i)(ii)sin(2x)h=sin(x)2s2sin(x)=sin(x)sin(2x)sin(2x)=12x=15°
Answered by mr W last updated on 16/Dec/23
Commented by mr W last updated on 16/Dec/23
AB=BC=2×BE  sin 2α=((BE)/(AB))=(1/2)  ⇒2α=30° ⇒α=15°
AB=BC=2×BEsin2α=BEAB=122α=30°α=15°

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