Question Number 201995 by Mingma last updated on 18/Dec/23
Answered by AST last updated on 18/Dec/23
$$\mathrm{2}{b}^{\mathrm{3}} −\mathrm{2}{b}^{\mathrm{2}} =\mathrm{2}{b}^{\mathrm{2}} \left({b}−\mathrm{1}\right)\Rightarrow\left({E}\right) \\ $$