Question Number 202039 by sonukgindia last updated on 19/Dec/23
Answered by mr W last updated on 19/Dec/23
Commented by mr W last updated on 19/Dec/23
$$\frac{{AB}}{{AD}}=\frac{{AC}}{{AE}}=\frac{\sqrt{\mathrm{3}}}{\mathrm{2}} \\ $$$$\Rightarrow\Delta{ABC}\sim\Delta{ADE} \\ $$$$\Rightarrow\alpha=\beta \\ $$$$?=\alpha+\mathrm{60}°+\mathrm{90}°−\beta=\mathrm{150}°\:\checkmark \\ $$