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If-p-9999-then-4p-3-p-2p-1-6p-3-




Question Number 202129 by MATHEMATICSAM last updated on 21/Dec/23
If p = 9999 then ((4p^3  − p)/((2p + 1)(6p − 3))) = ?
$$\mathrm{If}\:{p}\:=\:\mathrm{9999}\:\mathrm{then}\:\frac{\mathrm{4}{p}^{\mathrm{3}} \:−\:{p}}{\left(\mathrm{2}{p}\:+\:\mathrm{1}\right)\left(\mathrm{6}{p}\:−\:\mathrm{3}\right)}\:=\:? \\ $$
Answered by AST last updated on 21/Dec/23
((p(2p−1)(2p+1))/(3(2p+1)(2p−1)))=((p=9999)/3)=3333
$$\frac{{p}\left(\mathrm{2}{p}−\mathrm{1}\right)\left(\mathrm{2}{p}+\mathrm{1}\right)}{\mathrm{3}\left(\mathrm{2}{p}+\mathrm{1}\right)\left(\mathrm{2}{p}−\mathrm{1}\right)}=\frac{{p}=\mathrm{9999}}{\mathrm{3}}=\mathrm{3333} \\ $$

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