Question Number 202129 by MATHEMATICSAM last updated on 21/Dec/23
$$\mathrm{If}\:{p}\:=\:\mathrm{9999}\:\mathrm{then}\:\frac{\mathrm{4}{p}^{\mathrm{3}} \:−\:{p}}{\left(\mathrm{2}{p}\:+\:\mathrm{1}\right)\left(\mathrm{6}{p}\:−\:\mathrm{3}\right)}\:=\:? \\ $$
Answered by AST last updated on 21/Dec/23
$$\frac{{p}\left(\mathrm{2}{p}−\mathrm{1}\right)\left(\mathrm{2}{p}+\mathrm{1}\right)}{\mathrm{3}\left(\mathrm{2}{p}+\mathrm{1}\right)\left(\mathrm{2}{p}−\mathrm{1}\right)}=\frac{{p}=\mathrm{9999}}{\mathrm{3}}=\mathrm{3333} \\ $$