Question Number 202679 by Mingma last updated on 31/Dec/23
Answered by esmaeil last updated on 31/Dec/23
$$\curvearrowright\rightarrow<_{{hex}} =\mathrm{120}\rightarrow \\ $$$${tan}\mathrm{30}=\frac{{h}}{\frac{{a}}{\mathrm{2}}}\rightarrow{h}=\frac{\sqrt{\mathrm{3}}{a}}{\mathrm{6}} \\ $$$$\mathrm{2}\left(\frac{{a}}{\mathrm{2}}×\frac{\sqrt{\mathrm{3}}{a}}{\mathrm{6}}×\frac{\mathrm{1}}{\mathrm{2}}\right)=\mathrm{43}=\left({S}_{{blue}} +{S}_{{pink}} \right)\rightarrow \\ $$$$\sqrt{\mathrm{3}}{a}^{\mathrm{2}} =\mathrm{12}×\mathrm{43}\rightarrow{a}\cong\mathrm{17}.\mathrm{26}\rightarrow \\ $$$${A}_{{h}} =\mathrm{17}.\mathrm{26}×\mathrm{17}.\mathrm{26}−\left(\mathrm{2}×\mathrm{43}\right)=\mathrm{211}.\mathrm{91} \\ $$$$ \\ $$
Commented by Mingma last updated on 31/Dec/23
Perfect ��