place-1-25-in-table-5-5-in-such-away-that-the-sum-is-constant-in-all-directions-direction-

Question Number 202750 by esmaeil last updated on 02/Jan/24

p l a c e (1 \to 25)

i n t a b l e (5 \times 5) i n s u c h a w a y t h a t

t h e s u m i s c o n s t a n t i n a l l d i r e c t i o n s .

[∣ \underline{\bar{\times}} ∣] \to (d i r e c t i o n)

Commented by esmaeil last updated on 02/Jan/24

f o r e x a m p l e (3 \times 3)

[8] [1] [6]

[3] [5] [7]

[4] [9] [2]

Answered by Rasheed.Sindhi last updated on 02/Jan/24

65

\begin{array}{cccccc} 17 & 24 & 1 & 8 & 15 & 65 \\ 23 & 5 & 7 & 14 & 16 & 65 \\ 4 & 6 & 13 & 20 & 22 & 65 \\ 10 & 12 & 19 & 21 & 3 & 65 \\ 11 & 18 & 25 & 2 & 9 & 65 \\ 65 & 65 & 65 & 65 & 65 & 65 \end{array}

65 a r e s u m s o f r o w s

65 a r e s u m s o f c o l u m n s

65 a r e s u m s o f d i a g o n a l s

Commented by esmaeil last updated on 02/Jan/24

⋚

Commented by esmaeil last updated on 02/Jan/24

i t c a n b e s o l v e d f o r a l l t a b l e s

w i t h o d d n u m b e r o f r o w s a n d

c o l u m n s .

Commented by Rasheed.Sindhi last updated on 02/Jan/24

A l s o f o r e v e n o r d e r t h e r e a r e d i f f e r e n t

p a t t e r n s / r u l e s .

Answered by BaliramKumar last updated on 02/Jan/24

Commented by BaliramKumar last updated on 02/Jan/24

write 1 to 25 continuous and fit same colour box

start any number

2, 3, 4, 5, \dots \dots \dots 24, 25, 1

10, 11, 12, 13, \dots \dots \dots 24, 25, 1 \dots \dots . . 8, 9

Commented by esmaeil last updated on 02/Jan/24

c l e v e r s o l u t i o n .

e x c e l l e n t

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