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Question-202893




Question Number 202893 by sonukgindia last updated on 05/Jan/24
Answered by BaliramKumar last updated on 05/Jan/24
0.5 = h(cot37°−cot41°)  h = 2.830 km
0.5=h(cot37°cot41°)h=2.830km
Answered by AST last updated on 05/Jan/24
((sin(139))/g)=((sin(4))/(0.5))⇒g=((sin(139))/(2sin(4)))  ((sin(90))/g)=((sin(37))/h)⇒h=gsin(37)=((sin(139)sin(37))/(2sin(4)))  ≈2.83km
sin(139)g=sin(4)0.5g=sin(139)2sin(4)sin(90)g=sin(37)hh=gsin(37)=sin(139)sin(37)2sin(4)2.83km

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