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just-the-exact-real-root-please-x-6-1-x-4-3x-2-3-2x-3x-4-1-0-




Question Number 202964 by ajfour last updated on 06/Jan/24
just the exact real root please:  (x^6 −1)(x^4 +3x^2 −3)+2x(3x^4 −1)=0
$${just}\:{the}\:{exact}\:{real}\:{root}\:{please}: \\ $$$$\left({x}^{\mathrm{6}} −\mathrm{1}\right)\left({x}^{\mathrm{4}} +\mathrm{3}{x}^{\mathrm{2}} −\mathrm{3}\right)+\mathrm{2}{x}\left(\mathrm{3}{x}^{\mathrm{4}} −\mathrm{1}\right)=\mathrm{0} \\ $$

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