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Question Number 203035 by Frix last updated on 07/Jan/24

e = 2

Proof :

Let x = \frac{e + 2}{2}

2 x = e + 2

2 x (e - 2) = (e + 2) (e - 2)

2 e x - 4 x = e^{2} - 4

- 4 x + 4 = - 2 e x + e^{2}

x^{2} - 4 x + 4 = x^{2} - 2 e x + e^{2}

{(x - 2)}^{2} = {(x - e)}^{2}

\sqrt{{(x - 2)}^{2}} = \sqrt{{(x - e)}^{2}}

x - 2 = x - e

- 2 = - e

e = 2

Commented by Calculusboy last updated on 07/Jan/24

\boldsymbol n i c e \boldsymbol s i r

Commented by AST last updated on 07/Jan/24

2 x = e + 2 \Leftrightarrow 2 x (e - 2) = (e + 2) (e - 2) i s o n l y v a l i d

w h e n e \neq 2

\sqrt{{(x - 2)}^{2}} = \sqrt{{(x - e)}^{2}} \Rightarrow x - 2 = x - e i s o n l y v a l i d

w h e n x ⩾ 2 \land x ⩾ e

e h e r e a l s o h a s n o t h i n g t o d o w i t h {E u l e r}^{'} s

n u m b e r (\approx 2.718281) . S o, i t i s a c t i n g l i k e a

r a n d o m v a r i a b l e . I t c o u l d a l s o b e a, b, s, t, x \dots

Commented by Frix last updated on 08/Jan/24

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