Question-203211

Question Number 203211 by ajfour last updated on 12/Jan/24

Answered by MM42 last updated on 12/Jan/24

p^2 =2−2cosa q^2 =2−2sina ⇒(p^2 −2)^2 +(q^2 −2)^2 =4 ✓

$${p}^{\mathrm{2}} =\mathrm{2}−\mathrm{2}{cosa} \\ $$$${q}^{\mathrm{2}} =\mathrm{2}−\mathrm{2}{sina} \\ $$$$\Rightarrow\left({p}^{\mathrm{2}} −\mathrm{2}\right)^{\mathrm{2}} +\left({q}^{\mathrm{2}} −\mathrm{2}\right)^{\mathrm{2}} =\mathrm{4}\:\:\checkmark \\ $$$$ \\ $$

Commented by ajfour last updated on 12/Jan/24