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find-the-last-4-digits-of-2024-2023-

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Question Number 203270 by MrGHK last updated on 13/Jan/24
find the last 4 digits of 2024^(2023)
findthelast4digitsof20242023
Answered by Frix last updated on 14/Jan/24
Last 4 digits of 2024^n n=1 2024 Then a loop of length 50 f(n)=last 4 digits of 2024^n f(n)=f(n+50k); 2≤n≤51∧k∈N f(2023)=f(23)=7824
Last4digitsof2024nn=12024Thenaloopoflength50f(n)=last4digitsof2024nf(n)=f(n+50k);2⩽n⩽51∧k∈Nf(2023)=f(23)=7824

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