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Question-203352




Question Number 203352 by Mingma last updated on 17/Jan/24
Answered by witcher3 last updated on 17/Jan/24
sin(2x)=0⇒x=((kπ)/2),k∈Z  x^2 −5x+4=x^2 −(1+4)x+(1.4)=0⇒x∈{1,4 }  X=R−({1,4}∪{((kπ)/2),k∈Z})
$$\mathrm{sin}\left(\mathrm{2x}\right)=\mathrm{0}\Rightarrow\mathrm{x}=\frac{\mathrm{k}\pi}{\mathrm{2}},\mathrm{k}\in\mathbb{Z} \\ $$$$\mathrm{x}^{\mathrm{2}} −\mathrm{5x}+\mathrm{4}=\mathrm{x}^{\mathrm{2}} −\left(\mathrm{1}+\mathrm{4}\right)\mathrm{x}+\left(\mathrm{1}.\mathrm{4}\right)=\mathrm{0}\Rightarrow\mathrm{x}\in\left\{\mathrm{1},\mathrm{4}\:\right\} \\ $$$$\mathrm{X}=\mathbb{R}−\left(\left\{\mathrm{1},\mathrm{4}\right\}\cup\left\{\frac{\mathrm{k}\pi}{\mathrm{2}},\mathrm{k}\in\mathbb{Z}\right\}\right) \\ $$
Commented by Mingma last updated on 17/Jan/24
Perfect ��

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