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Question-203389




Question Number 203389 by sonukgindia last updated on 18/Jan/24
Answered by mr W last updated on 18/Jan/24
Commented by mr W last updated on 18/Jan/24
s=side length of square  a^2 +(s−x)^2 =s^2 +x^2   ⇒x=(a^2 /(2s))  (a/s)=(x/b)=(a^2 /(2sb))  ⇒(a/b)=2 ✓
$${s}={side}\:{length}\:{of}\:{square} \\ $$$${a}^{\mathrm{2}} +\left({s}−{x}\right)^{\mathrm{2}} ={s}^{\mathrm{2}} +{x}^{\mathrm{2}} \\ $$$$\Rightarrow{x}=\frac{{a}^{\mathrm{2}} }{\mathrm{2}{s}} \\ $$$$\frac{{a}}{{s}}=\frac{{x}}{{b}}=\frac{{a}^{\mathrm{2}} }{\mathrm{2}{sb}} \\ $$$$\Rightarrow\frac{{a}}{{b}}=\mathrm{2}\:\checkmark \\ $$

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