Question Number 203394 by professorleiciano last updated on 18/Jan/24
Answered by som(math1967) last updated on 18/Jan/24
$$\frac{\bigtriangleup{BPQ}}{\bigtriangleup{ABC}}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\Rightarrow\frac{{BQ}}{{BC}}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}} \\ $$$$\Rightarrow\frac{{BQ}}{\mathrm{2}}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\Rightarrow{BQ}=\frac{\mathrm{2}}{\:\sqrt{\mathrm{2}}}=\sqrt{\mathrm{2}}\:{cm} \\ $$