Question Number 203454 by Denis_volosenko352 last updated on 19/Jan/24
$$\sqrt{\mathrm{5}}+\sqrt{\mathrm{5}}={x} \\ $$$${x}×\mathrm{5}\pi=?\:{find}\:{all}\:{answers}\:{until}\:\mathrm{24}.\mathrm{01}.\mathrm{2024} \\ $$
Answered by MathematicalUser2357 last updated on 20/Jan/24
$${x}=\sqrt{\mathrm{5}}+\sqrt{\mathrm{5}}=\mathrm{2}\sqrt{\mathrm{5}} \\ $$$${x}×\mathrm{5}\pi=\mathrm{2}\sqrt{\mathrm{5}}×\mathrm{5}\pi=\mathrm{10}\pi\sqrt{\mathrm{5}} \\ $$