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d-3-y-dx-3-4-x-1-4-2-4y-




Question Number 203498 by ajfour last updated on 20/Jan/24
(d^(3 ) y/dx^3 )=4(x+(1/4))^2 −4y
$$\frac{{d}^{\mathrm{3}\:} {y}}{{dx}^{\mathrm{3}} }=\mathrm{4}\left({x}+\frac{\mathrm{1}}{\mathrm{4}}\right)^{\mathrm{2}} −\mathrm{4}{y} \\ $$

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