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x-4-cx-d-0-then-find-p-from-p-6-4-d-3-c-4-1-3-p-2-1-0-x-c-1-3-2-p-p-2-8-p-




Question Number 203497 by ajfour last updated on 20/Jan/24
x^4 +cx+d=0  then  find p  from  p^6 −4((d^( 3) /c^4 ))^(1/3) p^2 −1=0  x=(c^(1/3) /2)(p±(√(−p^2 −(8/p))) )
x4+cx+d=0thenfindpfromp64(d3c4)1/3p21=0x=c1/32(p±p28p)

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