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Question-203638




Question Number 203638 by thean0000 last updated on 24/Jan/24
Commented by thean0000 last updated on 24/Jan/24
help me
helpme
Commented by thean0000 last updated on 24/Jan/24
which one is answer
whichoneisanswer
Answered by esmaeil last updated on 24/Jan/24
z=x^2 y+3xy^4    { ((x=sin2t)),((y=cost)) :}→(dz/dt)]_(t=0) =?  z=4sin^2 tcos^3 t+6sintcos^5 t→(dz/dt)]_(t=0) =  4(2sintcos^4 t−3cos^2 tsin^3 t)+  6(cos^5 t−5cos^4 tsin^2 t)=  (0+0+0)+6(1−0)=6
z=x2y+3xy4{x=sin2ty=costdzdt]t=0=?z=4sintcos23t+6sintcos5tdzdt]t=0=4(2sintcos4t3cos2tsin3t)+6(cos5t5cos4tsin2t)=(0+0+0)+6(10)=6
Answered by MM42 last updated on 24/Jan/24
(dz/dt) =(dz/dx)×(dx/dt)+(dz/dy)×(dy/dt)  =(2xy+3y^4 )×2cos2t+(x^2 +6xy)(−sint)  t=0⇒(dz/dt)=6  ✓
dzdt=dzdx×dxdt+dzdy×dydt=(2xy+3y4)×2cos2t+(x2+6xy)(sint)t=0dzdt=6

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