Question Number 203648 by yaslm last updated on 24/Jan/24
Answered by Frix last updated on 24/Jan/24
$${w}\left({x}+\frac{{l}}{\mathrm{2}}\right)\left({x}−\frac{{l}}{\mathrm{2}}\left(\mathrm{1}−\mathrm{i}\right)\right)\left({x}−\frac{{l}}{\mathrm{2}}\left(\mathrm{1}+\mathrm{i}\right)\right)=\mathrm{0} \\ $$$${x}=−\frac{{l}}{\mathrm{2}}\vee{x}=\frac{{l}}{\mathrm{2}}\left(\mathrm{1}\pm\mathrm{i}\right) \\ $$
Commented by yaslm last updated on 24/Jan/24
thank you, what is the name of method