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Q-In-AB-C-AB-AC-b-and-BC-a-If-cos-A-a-2-b-2-then-find-the-value-of-b-a-




Question Number 203704 by mnjuly1970 last updated on 26/Jan/24
       Q: In AB^Δ C :  ( AB=AC=b ) and  ( BC=a ).                 If  ,  cos (A )= (a^2 /b^2 ) ,    then find the value of :                             (√((b/a) )) =?
Q:InABCΔ:(AB=AC=b)and(BC=a).If,cos(A)=a2b2,thenfindthevalueof:ba=?
Answered by esmaeil last updated on 26/Jan/24
BC^2 =AB^2 +AC^2 −2AB×ACcosA→  a^2 =b^2 +b^2 −2b^2 cosA→  3a^2 =2b^2 →(√(b/a))=((3/2))^(1/4)
BC2=AB2+AC22AB×ACcosAa2=b2+b22b2cosA3a2=2b2ba=324

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