Question Number 203693 by Numsey last updated on 26/Jan/24
Answered by MM42 last updated on 26/Jan/24
$${I}=\int\sqrt{\mathrm{2}}{cos}\frac{{x}}{\mathrm{2}}{dx}=\mathrm{2}\sqrt{\mathrm{2}}{sin}\frac{{x}}{\mathrm{2}}\:+{c} \\ $$
Commented by Frix last updated on 26/Jan/24
$$\sqrt{\mathrm{1}+\mathrm{cos}\:{x}}=\sqrt{\mathrm{2}}\mid\mathrm{cos}\:\frac{{x}}{\mathrm{2}}\mid \\ $$
Answered by esmaeil last updated on 26/Jan/24
$${I}=\mathrm{2}\sqrt{\mathrm{2}}\mid{sin}\frac{{x}}{\mathrm{2}}\mid+{c} \\ $$$${DomainI}=\left[\mathrm{0},+\infty\right) \\ $$$$ \\ $$