Question-203694 Tinku Tara January 26, 2024 Differential Equation 0 Comments FacebookTweetPin Question Number 203694 by Numsey last updated on 26/Jan/24 Answered by Calculusboy last updated on 26/Jan/24 Solution:bysubdirectly,weget00(indeterminant)letΞ=limxβ0(1+x)5x2βlimxβ0e5xx2+limxβ0sin(x2)x2Ξ=limxβ05(1+x)42xβlimxβ05e5x2x+1Ξ=limxβ020(1+x)32βlimxβ025e5x2+1Ξ=10limxβ0(1+x)3β252limexβ05x+1Ξ=10β252+1Ξ=β32=β1.5β΄limxβ0(1+x)5βe5x+sinx2x2=β32=β1.5 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-203695Next Next post: Question-203726 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.