Question-203822 Tinku Tara January 29, 2024 None 0 Comments FacebookTweetPin Question Number 203822 by 073 last updated on 29/Jan/24 Answered by esmaeil last updated on 29/Jan/24 1:1x=p→x→∞→p→0[x+1x]=[p+1)=1→Ω=limp→0sinpp=1 Answered by esmaeil last updated on 29/Jan/24 2:Ω=limx→1−2x(1−x)1−x=23:Ω=limx→0+[x]−xx=limx→00−xx=−1 Answered by MathematicalUser2357 last updated on 30/Jan/24 Whatis:[[x]] Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: How-many-bit-strings-of-length-10-do-not-have-four-consecutive-1s-Next Next post: lim-n-i-2-n-i-2-1-i-2- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.