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Question-203835




Question Number 203835 by patrice last updated on 29/Jan/24
Answered by MathematicalUser2357 last updated on 30/Jan/24
bruh
bruh
Commented by Frix last updated on 30/Jan/24
It′s not that hard...
Itsnotthathard
Answered by MrGaster last updated on 03/Nov/24
=∫_0 ^(√2) ((√(6−(√((5x^2 −6)^2 ))))/( (√5)))dx  =∫_0 ^(√2) ((√(6−(5x^2 −6)^2 ))/( (√5)))dx  =∫_0 ^(√2) ((√(6−(6−5x^2 )))/( (√5)))dx  =∫_0 ^(√2) ((√(5x^2 ))/( (√5)))dx  =∫_0 ^(√2) (((√5)x)/( (√5)))dx  =∫_0 ^(√2) x dx=(x^2 /2)∣_0 ^(√2)   =((((√2))^2 )/2)−(0^2 /2)  =(2/2)  =1
=026(5x26)25dx=026(5x26)25dx=026(65x2)5dx=025x25dx=025x5dx=02xdx=x2202=(2)22022=22=1
Commented by Frix last updated on 03/Nov/24
(5x^2 −6)^2 =25x^4 −60x^2 +36≠25x^4 −50x^2 +36
(5x26)2=25x460x2+3625x450x2+36

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