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I-A-5-1-B-3-5-C-5-2-ar-ABC-II-A-5-3-B-2-5-C-5-3-D-4-3-ar-ABCD-shortest-solution-




Question Number 204062 by BaliramKumar last updated on 05/Feb/24
I.       A(−5, −1); B(3, −5); C(5, 2)      ar(△ABC) = ?  II.     A(5, 3); B(2, 5); C(−5, 3); D(−4, −3)       ar(□ABCD) = ?  shortest solution
I.A(5,1);B(3,5);C(5,2)ar(ABC)=?II.A(5,3);B(2,5);C(5,3);D(4,3)ar(◻ABCD)=?shortestsolution
Answered by mr W last updated on 05/Feb/24
I.  A=∣(1/2) determinant (((3−(−5)),(−5−(−1))),((5−(−5)),(2−(−1))))∣   =∣(1/2) determinant ((8,(−4)),((10),3))∣  =((24+40)/2)=32  II.  A=∣(1/2) determinant (((−3),2),((−10),0))∣+∣(1/2) determinant (((−10),0),((−9),(−6)))∣     =((20)/2)+((60)/2)=40
I.A=∣12|3(5)5(1)5(5)2(1)|=∣12|84103|=24+402=32II.A=∣12|32100|+12|10096|=202+602=40
Commented by BaliramKumar last updated on 05/Feb/24
any other solution
anyothersolution
Commented by mr W last updated on 05/Feb/24
surely there are other methods.  but this is the shortest solution  i think.
surelythereareothermethods.butthisistheshortestsolutionithink.
Answered by AST last updated on 05/Feb/24
AB=(√(80));BC=(√(53));AC=(√(109))  [ABC]=(√((((√(80))+(√(53))+(√(109)))((√(80))+(√(53))−(√(109)((√(80))+(√(109))−(√(53)))((√(109))+(√(53))−(√(80))))))/(16)))  =(√(((24+2(√(80×53)))(−24+2(√(53×80))))/(16)))=(√((4×53×80−24^2 )/(16)))  =32
AB=80;BC=53;AC=109[ABC]=(80+53+109)(80+53109)(80+10953)(109+5380)16=(24+280×53)(24+253×80)16=4×53×8024216=32
Answered by AST last updated on 05/Feb/24
Translate any vertex say C(5,2)→C(0,0)  ⇒A(−5,−1)→A(−10,−3)∧B(3,−5)→B(−2,−7)  ⇒[ABC]=∣(1/2) determinant (((−10),(−2)),((−3),(−7)))∣=((64)/2)=32
TranslateanyvertexsayC(5,2)C(0,0)A(5,1)A(10,3)B(3,5)B(2,7)[ABC]=∣12|10237|∣=642=32
Answered by AST last updated on 05/Feb/24
Let C(−5,3)→(0,0);[ABCD]=[ABD]+[BCD]  ⇒A(5,3)→A(10,0);B(2,5)→B(7,2);D→(1,−6)  ⇒[BCD]=∣(1/2) determinant ((7,1),(2,(−6)))∣=22  Let A→(0,0)⇒B→(−3,2);D→(−9,−6)  ⇒[ABD]=∣(1/2) determinant (((−3),(−9)),(2,(−6)))∣=18⇒[ABCD]=40
LetC(5,3)(0,0);[ABCD]=[ABD]+[BCD]A(5,3)A(10,0);B(2,5)B(7,2);D(1,6)[BCD]=∣12|7126|∣=22LetA(0,0)B(3,2);D(9,6)[ABD]=∣12|3926|∣=18[ABCD]=40

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