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sin-2-2-sin-2-90-gt-gt-0-




Question Number 204072 by Red1ight last updated on 05/Feb/24
((sin^2  θ)/2)=sin 2θ? (90°>θ>0°)
$$\frac{\mathrm{sin}^{\mathrm{2}} \:\theta}{\mathrm{2}}=\mathrm{sin}\:\mathrm{2}\theta?\:\left(\mathrm{90}°>\theta>\mathrm{0}°\right) \\ $$
Answered by AST last updated on 05/Feb/24
sin^2 θ=4sinθcosθ⇒tanθ=4⇒θ=tan^(−1) (4)≈75.96°
$${sin}^{\mathrm{2}} \theta=\mathrm{4}{sin}\theta{cos}\theta\Rightarrow{tan}\theta=\mathrm{4}\Rightarrow\theta={tan}^{−\mathrm{1}} \left(\mathrm{4}\right)\approx\mathrm{75}.\mathrm{96}° \\ $$

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