what-does-mean-that-we-say-C-F-in-40-

Question Number 204230 by Davidtim last updated on 09/Feb/24

w h a t d o e s m e a n t h a t w e s a y C^{°} = F^{°}

i n - 40 ?

Commented by mr W last updated on 10/Feb/24

g e n e r a l l y t h e t e m p e r a t u r e v a l u e i n

u n i t ° C (C e l s i u s) i s n o t t h e s a m e a s

i t s v a l u e i n u n i t ° F (F a h r e n h e i t),

f o r e x a m p l e 10 ° C = 50 ° F,

- 20 ° C = - 4 ° F . b u t - 40 ° C = - 40 ° F .

Commented by Davidtim last updated on 10/Feb/24

t h a n k s

Commented by Davidtim last updated on 10/Feb/24

w o u l d y o u m i n d f i n d t h e \frac{d}{d x} (x!) ?

Commented by mr W last updated on 10/Feb/24

x! = Γ (x + 1)

\frac{d (x!)}{d x} = x! ψ^{(0)} (x + 1)

Commented by Davidtim last updated on 12/Feb/24

w o u l d y o u m i n d t o s o l v e w i t h o u t g a m m a

o r b i t t a f u n c t i o n ?

Commented by mr W last updated on 12/Feb/24

i c a n n o t . i f y o u c a n, p l e a s e s h a r e .

Commented by Davidtim last updated on 12/Feb/24

y = x!

l n y = l n (x!)

l n y = l n [x \cdot (x - 1) \cdot (x - 2) \cdot (x - 3) \cdot \cdot \cdot 3 \cdot 2 \cdot 1]

l n y = l n x + l n (x - 1) + l n (x - 2) + l n (x - 3) + \cdot \cdot \cdot + l n 1

\frac{y^{^{'}}}{y} = \frac{1}{x} + \frac{1}{x - 1} + \frac{1}{x - 2} + \cdot \cdot \cdot + 0

y^{^{'}} = y (\frac{1}{x} + \frac{1}{x - 1} + \frac{1}{x - 2} + \cdot \cdot)

y^{^{'}} = x! (\frac{1}{x} + \frac{1}{x - 1} + \frac{1}{x - 2} + \cdot \cdot \cdot)

Commented by Davidtim last updated on 12/Feb/24

y = x!

l n y = l n (x!)

l n y = l n [x \cdot (x - 1) \cdot (x - 2) \cdot (x - 3) \cdot \cdot \cdot 3 \cdot 2 \cdot 1]

l n y = l n x + l n (x - 1) + l n (x - 2) + l n (x - 3) + \cdot \cdot \cdot + l n 1

\frac{y^{^{'}}}{y} = \frac{1}{x} + \frac{1}{x - 1} + \frac{1}{x - 2} + \cdot \cdot \cdot + 0

y^{^{'}} = y (\frac{1}{x} + \frac{1}{x - 1} + \frac{1}{x - 2} + \cdot \cdot)

y^{^{'}} = x! (\frac{1}{x} + \frac{1}{x - 1} + \frac{1}{x - 2} + \cdot \cdot \cdot)

Commented by mr W last updated on 12/Feb/24

w h e n y o u t a k e x! = x (x - 1) (x - 2) \dots 3 \times 2 \times 1

y o u a s s u m e x \in N, t h e n x! i s n o t

a c o n t i n u o u s f u n c t i o n a n d t h u s n o t

d i f f e r e n t i a b l e .

Commented by Davidtim last updated on 13/Feb/24

h o w c a n s o l v e w i t h o u t g a m m a f u n c t i o n ?

Answered by Satyam1234 last updated on 09/Feb/24

F = C \times \frac{9}{5} + 32

L e t C = F = x

x = \frac{9 x}{5} + 32

5 x = 9 x + 160

- 4 x = 160

x = - 40

Commented by Davidtim last updated on 09/Feb/24

I {d o n}^{'} t u n d e r s t a n t t h e m a i n m e a n o t

t h i s .

d e s c r i b e t h e m a i n m e a n o f t h e - 40 .

Commented by JDamian last updated on 10/Feb/24

the main purpose is to make you to solve

a first degree equation

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