Question Number 204389 by Ngarmadji last updated on 15/Feb/24
Answered by Frix last updated on 15/Feb/24
$$\frac{\mathrm{2}{x}}{\mathrm{3}}−\frac{\mathrm{2}{x}}{\mathrm{5}}=\mathrm{1}\:\:\frac{{x}}{\mathrm{3}}−\frac{{x}}{\mathrm{5}}=\frac{\mathrm{1}}{\mathrm{2}}\:\:\mathrm{5}{x}−\mathrm{3}{x}=\frac{\mathrm{15}}{\mathrm{2}}\:\:{x}=\frac{\mathrm{15}}{\mathrm{4}} \\ $$$$\frac{\mathrm{3}{x}}{\mathrm{5}}−\frac{\mathrm{2}{x}}{\mathrm{15}}+\frac{{x}}{\mathrm{3}}=−\frac{\mathrm{7}}{\mathrm{15}}\:\:\frac{\mathrm{9}{x}−\mathrm{2}{x}+\mathrm{5}{x}}{\mathrm{15}}=−\frac{\mathrm{7}}{\mathrm{15}}\:\:…\:{x}=−\frac{\mathrm{7}}{\mathrm{12}} \\ $$