Question Number 204441 by peter frank last updated on 17/Feb/24
Commented by Frix last updated on 17/Feb/24
$$\mathrm{3}\:\mathrm{circles}\:\mathrm{plus}\:\mathrm{4}\:\mathrm{times}\:\left(\mathrm{6}\:\mathrm{minus}\:\mathrm{4}\:\mathrm{radii}\right)\:\Rightarrow \\ $$$$\mathrm{perimeter}\:=\:\mathrm{6}\pi+\mathrm{8} \\ $$
Commented by peter frank last updated on 17/Feb/24
$$\mathrm{thanks} \\ $$