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Question-204533

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Question Number 204533 by bello6646 last updated on 20/Feb/24
Answered by MM42 last updated on 20/Feb/24
ln((ax)/b)=u⇒I=ln(ln(a/b)x)+c
$${ln}\frac{{ax}}{{b}}={u}\Rightarrow{I}={ln}\left({ln}\frac{{a}}{{b}}{x}\right)+{c} \\ $$

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