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f-x-x-3-16x-2-57x-1-f-a-0-f-b-0-f-c-0-a-1-5-b-1-5-c-1-5-




Question Number 204595 by SEKRET last updated on 22/Feb/24
              f(x) = x^3  − 16x^2  − 57x +1               f(a)= 0          f(b)=0          f(c)=0              (a)^(1/5)  + ((b ))^(1/5)  + ((c ))^(1/5)  = ?
f(x)=x316x257x+1f(a)=0f(b)=0f(c)=0a5+b5+c5=?
Answered by mr W last updated on 22/Feb/24
t=(x)^(1/5) ⇒x=t^5   t^(15) −16t^(10) −57t^5 +1=0  (t^3 −t^2 −2t+1)(t^(12) +t^(11) +...+2t+1)=0  t^3 −t^2 −2t+1=0  ⇒(a)^(1/5) +(b)^(1/5) +(c)^(1/5) =t_1 +t_2 +t_3 =1 ✓
t=x5x=t5t1516t1057t5+1=0(t3t22t+1)(t12+t11++2t+1)=0t3t22t+1=0a5+b5+c5=t1+t2+t3=1
Commented by SEKRET last updated on 22/Feb/24
  thank you sir
thankyousir
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