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f-x-sgn-x-f-x-d-dx-f-x-




Question Number 204688 by Davidtim last updated on 25/Feb/24
f(x)=sgn(x);     f^′ (x)=(d/dx)[f(x)]=?
f(x)=sgn(x);f(x)=ddx[f(x)]=?
Answered by Faetmaaa last updated on 27/Feb/24
(d/dx)[f∣_(]−∞, 0[) (x)] = (d/dx)[f∣_(]0, +∞[) (x)] = 0
ddx[f],0[(x)]=ddx[f]0,+[(x)]=0

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