Question Number 204866 by mathlove last updated on 29/Feb/24
$$\int\:\frac{{x}+\mathrm{3}}{{x}^{\mathrm{2}} \sqrt{\mathrm{2}{x}+\mathrm{3}}}\:{dx}=? \\ $$
Answered by Frix last updated on 29/Feb/24
$$\int\frac{{x}+\mathrm{3}}{{x}^{\mathrm{2}} \sqrt{\mathrm{2}{x}+\mathrm{3}}}{dx}\:\overset{{t}=\frac{\sqrt{\mathrm{2}{x}+\mathrm{3}}}{{x}}} {=}−\int{dt}=−{t}=−\frac{\sqrt{\mathrm{2}{x}+\mathrm{3}}}{{x}}+{C} \\ $$