Question Number 204910 by universe last updated on 01/Mar/24
Commented by witcher3 last updated on 02/Mar/24
$$\mathrm{is}\:\mathrm{This}\:\mathrm{correct}\:\mathrm{formes}? \\ $$
Answered by witcher3 last updated on 01/Mar/24
$$\mathrm{retchek}\:\mathrm{sir}\: \\ $$$$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\mathrm{x}^{\mathrm{2}} }{\left(\mathrm{1}+\mathrm{x}^{\mathrm{2}} \right)}\left(\frac{\mathrm{1}−\mathrm{xtan}\:\left(\mathrm{x}\right)+\mathrm{tan}\left(\mathrm{x}\right)−\mathrm{x}}{\mathrm{1}−\mathrm{xtan}\left(\mathrm{x}\right)+\mathrm{tan}\left(\mathrm{x}\right)+\mathrm{x}}\right)\mathrm{dx}\:\:? \\ $$
Commented by universe last updated on 02/Mar/24
$${yes}\:{sir} \\ $$
Answered by MathematicalUser2357 last updated on 04/Mar/24
$${why}\:\int_{\mathrm{0}} ^{\mathrm{1}} \left(\frac{{x}^{\mathrm{2}} }{{x}^{\mathrm{2}} +\mathrm{1}}\right)\left(\frac{\mathrm{1}−{x}\mathrm{tan}\:{x}+\mathrm{tan}\:{x}−{x}}{\mathrm{1}−{x}\mathrm{tan}\:{x}−\mathrm{tan}\:{x}−{x}}\right){dx}? \\ $$