Given-A-B-a-b-A-C-b-c-B-C-b-d-then-A-C-A-B-B-C-

Question Number 205070 by dimentri last updated on 07/Mar/24

Given {\begin{cases} A \cap B = {a, b} \\ A \cap C = {b, c} \\ B \cap C = {b, d} \end{cases}

then (A \cap C) + (A \cap B) + (B \cap C)

Commented by JDamian last updated on 07/Mar/24

D o y o u m e a n (A \cap C) \cup (A \cap B) \cup (B \cap C) ?

Commented by cortano12 last updated on 07/Mar/24

no

Commented by A5T last updated on 07/Mar/24

“ +^{″} g e n e r a l l y i s u s e d t o s u m c a r d i n a l i t y o f s e t s .

A r e y o u r e f e r r i n g t o t h a t ?

Commented by cortano12 last updated on 07/Mar/24

A + B = (A \cup B) - (A \cap B)

or A + B = (A - B) \cup (B - A)

Commented by A5T last updated on 07/Mar/24

T h e n D = (A \cap C) + (A \cap B) = {a, c}

D + (B \cap C) = (A \cap C) + (A \cap B) + (B \cap C) = {a, b, c, d}

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