sinx-cosx-1-x-

Question Number 205218 by hardmath last updated on 13/Mar/24

∣ sinx ∣ + ∣ cosx ∣ = 1

\Rightarrow x = ?

Answered by Sutrisno last updated on 13/Mar/24

{(∣ sinx ∣ + ∣ cosx ∣)}^{2} = 1^{2}

{s i n}^{2} x + 2 ∣ s i n x ∣∣ c o s x ∣ + {c o s}^{2} x = 1

∣ s i n 2 x ∣ + 1 = 1

∣ s i n 2 x ∣= 0

2 x = 0 + k . 2 π \to x = k . π

2 x = π - 0 + k . 2 π \to x = \frac{π}{2} + k . π

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