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If-a-1-b-1-c-1-8-Then-a-2-b-2-c-2-3-




Question Number 205422 by hardmath last updated on 20/Mar/24
If  (a + 1)(b + 1)(c + 1) = 8  Then:  a^2  + b^2  + c^2  ≥ 3
If(a+1)(b+1)(c+1)=8Then:a2+b2+c23
Answered by A5T last updated on 20/Mar/24
a+1+b+1+c+1≥3(((a+1)(b+1)(c+1)))^(1/3) =6  ⇒a+b+c≥3  (√3)(√(a^2 +b^2 +c^2 ))≥a+b+c⇒a^2 +b^2 +c^2 ≥3
a+1+b+1+c+13(a+1)(b+1)(c+1)3=6a+b+c33a2+b2+c2a+b+ca2+b2+c23

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