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Question-205492




Question Number 205492 by BaliramKumar last updated on 22/Mar/24
Answered by cortano12 last updated on 22/Mar/24
 ⇒Π_(i=1) ^5 T_(i ) = T_3 ^5  = 3^5 = 243
$$\:\Rightarrow\underset{\mathrm{i}=\mathrm{1}} {\overset{\mathrm{5}} {\prod}}\mathrm{T}_{\mathrm{i}\:} =\:\mathrm{T}_{\mathrm{3}} ^{\mathrm{5}} \:=\:\mathrm{3}^{\mathrm{5}} =\:\mathrm{243} \\ $$
Commented by BaliramKumar last updated on 22/Mar/24
thanks
$$\mathrm{thanks} \\ $$
Answered by Rasheed.Sindhi last updated on 22/Mar/24
let the terms are: (3/r^2 ),(3/r),3,3r,3r^2   (3/r^2 )∙(3/r)∙3∙3r∙3r^2 =3^5 =243
$${let}\:{the}\:{terms}\:{are}:\:\frac{\mathrm{3}}{{r}^{\mathrm{2}} },\frac{\mathrm{3}}{{r}},\mathrm{3},\mathrm{3}{r},\mathrm{3}{r}^{\mathrm{2}} \\ $$$$\frac{\mathrm{3}}{\cancel{{r}^{\mathrm{2}} }}\centerdot\frac{\mathrm{3}}{\cancel{{r}}}\centerdot\mathrm{3}\centerdot\mathrm{3}\cancel{{r}}\centerdot\mathrm{3}\cancel{{r}^{\mathrm{2}} }=\mathrm{3}^{\mathrm{5}} =\mathrm{243} \\ $$
Commented by BaliramKumar last updated on 22/Mar/24
thanks
$$\mathrm{thanks} \\ $$

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