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Question-205496




Question Number 205496 by cortano12 last updated on 22/Mar/24
Answered by Frix last updated on 22/Mar/24
x>0  t=(x)^(1/3)   log_2  (1+t) =3log_7  x  Obviously t=7  x=7^3 =343  If there was no obvious solution we could  only approximate.
$${x}>\mathrm{0} \\ $$$${t}=\sqrt[{\mathrm{3}}]{{x}} \\ $$$$\mathrm{log}_{\mathrm{2}} \:\left(\mathrm{1}+{t}\right)\:=\mathrm{3log}_{\mathrm{7}} \:{x} \\ $$$$\mathrm{Obviously}\:{t}=\mathrm{7} \\ $$$${x}=\mathrm{7}^{\mathrm{3}} =\mathrm{343} \\ $$$$\mathrm{If}\:\mathrm{there}\:\mathrm{was}\:\mathrm{no}\:\mathrm{obvious}\:\mathrm{solution}\:\mathrm{we}\:\mathrm{could} \\ $$$$\mathrm{only}\:\mathrm{approximate}. \\ $$

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